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Popular >

yy^'=t

Solution

y y^{^{'}} = t

Solution

y = t^{2} + c_{1}, y = - t^{2} + c_{1}

Solution steps

y y^{'} (t) = t

Solve separable ODE:

y = t^{2} + c_{1}, y = - t^{2} + c_{1}

y = t^{2} + c_{1}, y = - t^{2} + c_{1}

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Frequently Asked Questions (FAQ)

What is the solution for yy^'=t ?
The solution for yy^'=t is y=sqrt(t^2+c_{1)},y=-sqrt(t^2+c_{1)}