en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3x^'+6x=4,x(0)=2

Solution

3 x^{^{'}} + 6 x = 4, x (0) = 2

Solution

x = \frac{2}{3} + \frac{4}{3 e ^{2 t}}

Solution steps

3 x^{'} (t) + 6 x = 4

Solve linear ODE:

x = \frac{2}{3} + \frac{4}{3 e ^{2 t}}

x = \frac{2}{3} + \frac{4}{3 e ^{2 t}}

Popular Examples

derivative of 1100sqrt(x^2-0.2x)

\frac{d}{d x} (1100 x^{2} - 0.2 x)

taylor sin(2x)taylor

sin (2 x)

derivative of 16x

\frac{d}{d x} (16 x)

derivative of (5a+1)^2 derivative of

(5 a + 1)^{2}

integral from 0.2 to 0.4 of (200x)

\int_{0.2}^{0.4} (200 x) d x

Frequently Asked Questions (FAQ)

What is the solution for 3x^'+6x=4,x(0)=2 ?
The solution for 3x^'+6x=4,x(0)=2 is x= 2/3+4/(3e^{2t)}