What is the derivative of x^3+2x^2-x-1 ?

The derivative of x^3+2x^2-x-1 is 3x^2+4x-1

What is the first derivative of x^3+2x^2-x-1 ?

The first derivative of x^3+2x^2-x-1 is 3x^2+4x-1

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\frac{d}{d x} (x^{3} + 2 x^{2} - x - 1)

3 x^{2} + 4 x - 1

Solution steps

\frac{d}{d x} (x^{3} + 2 x^{2} - x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (2 x^{2}) - \frac{d x}{d x} - \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 3 x^{2} + 4 x - 1 - 0

Simplify

= 3 x^{2} + 4 x - 1

\int_{1}^{2} \frac{x ^{2} + 1}{x ^{2}} d x

sin (t + 1)

\int_{0}^{4} x^{2} - 4 x d x

\frac{1}{t + 1}

What is the derivative of x^3+2x^2-x-1 ?
The derivative of x^3+2x^2-x-1 is 3x^2+4x-1
What is the first derivative of x^3+2x^2-x-1 ?
The first derivative of x^3+2x^2-x-1 is 3x^2+4x-1