What is the integral of 3/(sqrt(x+4)) ?

The integral of 3/(sqrt(x+4)) is 6sqrt(x+4)+C

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integral of 3/(sqrt(x+4))

\int \frac{3}{x + 4} d x

6 x + 4 + C

Solution steps

\int \frac{3}{x + 4} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int \frac{1}{x + 4} d x

Apply u-substitution

: \int 2 d u

= 3 \cdot \int 2 d u

Integral of a constant:

\int a d x = a x

= 3 \cdot 2 u

Substitute back

u = x + 4

= 3 \cdot 2 x + 4

Simplify

= 6 x + 4

Add a constant to the solution

= 6 x + 4 + C

f (x) = x^{3} + x, at x = 2

cos (sin^{2} (x - 2))

x \to 0 + lim (arctan (ln (0)))

\frac{\partial}{\partial x} (4 x^{2} y^{3} + 1)

\frac{d}{d x} (\frac{3 x + 2}{2 x + 3})

What is the integral of 3/(sqrt(x+4)) ?
The integral of 3/(sqrt(x+4)) is 6sqrt(x+4)+C