What is the tangent of y=-9x^2,\at x=8 ?

The tangent of y=-9x^2,\at x=8 is y=-144x+576

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tangent of y=-9x^2,\at x=8

tangent of

y = - 9 x^{2}, at x = 8

y = - 144 x + 576

Solution steps

Find the tangent point:

(8, - 576)

Find the slope of

y = - 9 x^{2} : \frac{d y}{d x} = - 18 x

Compute the slope of

y = - 9 x^{2}

x = 8 : m = - 144

Find the line with slope m=

- 144

and passing through

(8, - 576) : y = - 144 x + 576

y = - 144 x + 576

y^{^{''}} = x^{2} + 1

y = 1 + (2 x + 1)^{8}

\int (x^{2} + 1) n x d x

\int_{8}^{R} \frac{1}{x ^{2} - 9 x + 18} d x

f (x) = \frac{6}{3 x + 1}, (- 1, - 3)

What is the tangent of y=-9x^2,\at x=8 ?
The tangent of y=-9x^2,\at x=8 is y=-144x+576