What is the integral of ((2x-4))/((x-2)^2) ?

The integral of ((2x-4))/((x-2)^2) is 2ln|x-2|+C

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integral of ((2x-4))/((x-2)^2)

\int \frac{( 2 x - 4 )}{( x - 2 ) ^{2}} d x

2 ln ∣ x - 2 ∣ + C

Solution steps

\int \frac{2 x - 4}{( x - 2 ) ^{2}} d x

Expand

\frac{2 x - 4}{( x - 2 ) ^{2}} : \frac{2 x}{( x - 2 ) ^{2}} - \frac{4}{( x - 2 ) ^{2}}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2 x}{( x - 2 ) ^{2}} d x - \int \frac{4}{( x - 2 ) ^{2}} d x

\int \frac{2 x}{( x - 2 ) ^{2}} d x = 2 (ln ∣ x - 2 ∣ - \frac{2}{x - 2})

\int \frac{4}{( x - 2 ) ^{2}} d x = - \frac{4}{x - 2}

= 2 (ln ∣ x - 2 ∣ - \frac{2}{x - 2}) - (- \frac{4}{x - 2})

Simplify

2 (ln ∣ x - 2 ∣ - \frac{2}{x - 2}) - (- \frac{4}{x - 2}) : 2 ln ∣ x - 2 ∣

= 2 ln ∣ x - 2 ∣

Add a constant to the solution

= 2 ln ∣ x - 2 ∣ + C

\frac{d y}{d x} = e^{- 2 x}

\frac{d y}{d x} = 3 y - x^{2} y

\frac{d}{d x} (tan (1))

x \to 1 lim (\frac{4}{x ^{3} - 1})

ln (\frac{6 - x}{6 + x})

What is the integral of ((2x-4))/((x-2)^2) ?
The integral of ((2x-4))/((x-2)^2) is 2ln|x-2|+C