What is the derivative of ln(x+y) ?

The derivative of ln(x+y) is 1/(x+y)

What is the first derivative of ln(x+y) ?

The first derivative of ln(x+y) is 1/(x+y)

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derivative of

ln (x + y)

\frac{1}{x + y}

Solution steps

\frac{d}{d x} (ln (x + y))

Treat

y

as a constant

Apply the chain rule:

\frac{1}{x + y} \frac{d}{d x} (x + y)

= \frac{1}{x + y} \frac{d}{d x} (x + y)

\frac{d}{d x} (x + y) = 1

= \frac{1}{x + y} \cdot 1

Simplify

= \frac{1}{x + y}

\frac{\partial}{\partial z} (cos (z w (z)))

x \to 0 lim (\frac{4 ^{x} - 7 ^{x}}{x})

\frac{\partial}{\partial x} (e^{- 6 x} cos (2 π t))

\int (3 x - 2 x^{- 3}) d x

\frac{π x}{2}

What is the derivative of ln(x+y) ?
The derivative of ln(x+y) is 1/(x+y)
What is the first derivative of ln(x+y) ?
The first derivative of ln(x+y) is 1/(x+y)