What is the solution for 2+(dy)/(dx)=sqrt(2x+y) ?

The solution for 2+(dy)/(dx)=sqrt(2x+y) is y=(x^2+c_{1}^2)/4+(c_{1}x)/2-2x

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2+(dy)/(dx)=sqrt(2x+y)

2 + \frac{d y}{d x} = 2 x + y

y = \frac{x ^{2} + c _{1}^{2}}{4} + \frac{c _{1} x}{2} - 2 x

Solution steps

2 + \frac{d y}{d x} = 2 x + y

Solve using substitution:

y = \frac{x ^{2} + c _{1}^{2}}{4} + \frac{c _{1} x}{2} - 2 x

y = \frac{x ^{2} + c _{1}^{2}}{4} + \frac{c _{1} x}{2} - 2 x

\frac{d}{d x} (\frac{in x}{x})

x \to 8 lim (e^{\frac{3}{( x - 8 )}})

\int \frac{2}{x - 2} d x

\int arccsc (\frac{x}{2}) d x

y^{^{''}} - 8 y^{^{'}} + 13 y = 0

What is the solution for 2+(dy)/(dx)=sqrt(2x+y) ?
The solution for 2+(dy)/(dx)=sqrt(2x+y) is y=(x^2+c_{1}^2)/4+(c_{1}x)/2-2x