What is the integral of 1/(y^{2/3)} ?

The integral of 1/(y^{2/3)} is 3y^{1/3}+C

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integral of 1/(y^{2/3)}

\int \frac{1}{y ^{\frac{2}{3}}} d y

3 y^{\frac{1}{3}} + C

Solution steps

\int \frac{1}{y ^{\frac{2}{3}}} d y

Apply the Power Rule

: 3 y^{\frac{1}{3}}

= 3 y^{\frac{1}{3}}

Add a constant to the solution

= 3 y^{\frac{1}{3}} + C

\frac{d ^{2}}{d x ^{2}} (\frac{2}{1 + x ^{2}})

\frac{d}{d x} (- x + 1)

\int π^{x} - x^{- 1} d x

\int_{7}^{14} - 30 x^{2} + 340 x d x

x \to i lim (\frac{x ^{4} - 1}{x - i})