What is the integral of cos(1+5t) ?

The integral of cos(1+5t) is 1/5 sin(1+5t)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of cos(1+5t)

\int cos (1 + 5 t) d t

\frac{1}{5} sin (1 + 5 t) + C

Solution steps

\int cos (1 + 5 t) d t

Apply u-substitution

: \int cos (u) \frac{1}{5} d u

= \int cos (u) \frac{1}{5} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{5} sin (u)

Substitute back

u = 1 + 5 t

= \frac{1}{5} sin (1 + 5 t)

Add a constant to the solution

= \frac{1}{5} sin (1 + 5 t) + C

\int x (arctan (x))^{2} d x

\int \frac{tan ( x )}{cos ^{3} ( x )} d x

\frac{d y}{y ^{2} - 4} = d x

\frac{\partial}{\partial x} (- 3 x)

\int \frac{1}{x ^{2}} - \frac{1}{x x} + 5 d x

What is the integral of cos(1+5t) ?
The integral of cos(1+5t) is 1/5 sin(1+5t)+C