What is the tangent of g(x)=7sqrt(x),\at x=9 ?

The tangent of g(x)=7sqrt(x),\at x=9 is y= 7/6 x+21/2

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tangent of g(x)=7sqrt(x),\at x=9

tangent of

g (x) = 7 x, at x = 9

y = \frac{7}{6} x + \frac{21}{2}

Solution steps

Find the tangent point:

(9, 21)

Find the slope of

g (x) = 7 x : \frac{d g ( x )}{d x} = \frac{7}{2 x}

Compute the slope of

g (x) = 7 x

x = 9 : m = \frac{7}{6}

Find the line with slope m=

\frac{7}{6}

and passing through

(9, 21) : y = \frac{7}{6} x + \frac{21}{2}

y = \frac{7}{6} x + \frac{21}{2}

\frac{d y}{d t} = 1600 - \frac{4 y}{170}

\frac{\partial}{\partial x} (\frac{x ^{2} y - 1}{x ^{2}})

\frac{d}{d x} (21 x)

\frac{\partial}{\partial x} (20 - x^{2} - 7 y^{2})

\frac{d}{d x} (ln (\frac{1 + e ^{x}}{1 - e ^{x}}))

What is the tangent of g(x)=7sqrt(x),\at x=9 ?
The tangent of g(x)=7sqrt(x),\at x=9 is y= 7/6 x+21/2