What is the sum from n=0 to infinity of 8^n ?

The sum from n=0 to infinity of 8^n is diverges

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sum from n=0 to infinity of 8^n

n = 0 \sum \infty 8^{n}

diverges

Solution steps

n = 0 \sum \infty 8^{n}

Apply Series Geometric Test:

diverges

= diverges

\frac{d}{d x} (\frac{2}{( 5 x + 1 ) ^{3}})

\int 96 - 32 t d t

y^{^{'}} = x e^{6}

\int \frac{( x ^{2} + 1 ) ( x ^{4} - x ^{2} + 1 )}{2 x ^{3}} d x

What is the sum from n=0 to infinity of 8^n ?
The sum from n=0 to infinity of 8^n is diverges