What is the sum from n=1 to infinity of ne^{-4n} ?

The sum from n=1 to infinity of ne^{-4n} is converges

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sum from n=1 to infinity of ne^{-4n}

n = 1 \sum \infty n e^{- 4 n}

converges

Solution steps

n = 1 \sum \infty n e^{- 4 n}

Apply Series Ratio Test:

converges

= converges

y = x^{4} + 9 x^{2} - x

\int \frac{1}{2} sec^{2} (5 x) d x

x + \frac{2}{x}

36 = 9 x^{2} - 4 y^{2}

What is the sum from n=1 to infinity of ne^{-4n} ?
The sum from n=1 to infinity of ne^{-4n} is converges