What is the derivative of ln(3x+1) ?

The derivative of ln(3x+1) is 3/(3x+1)

What is the first derivative of ln(3x+1) ?

The first derivative of ln(3x+1) is 3/(3x+1)

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derivative of

ln (3 x + 1)

\frac{3}{3 x + 1}

Solution steps

\frac{d}{d x} (ln (3 x + 1))

Apply the chain rule:

\frac{1}{3 x + 1} \frac{d}{d x} (3 x + 1)

= \frac{1}{3 x + 1} \frac{d}{d x} (3 x + 1)

\frac{d}{d x} (3 x + 1) = 3

= \frac{1}{3 x + 1} \cdot 3

Simplify

\frac{1}{3 x + 1} \cdot 3 : \frac{3}{3 x + 1}

= \frac{3}{3 x + 1}

x \to 0 + lim (sin (\frac{1}{x}))

\int_{0}^{4} 6 x + \frac{1}{( x + 3 ) ^{2}} d x

\frac{d}{d x} (- x^{3} + 9 x^{2} - 24 x + 5)

\frac{\partial}{\partial x} (3 x^{2} - 2 x y - 4 y^{2})

\frac{d y}{d t} \cdot \frac{1}{4} + y = cos (t)

What is the derivative of ln(3x+1) ?
The derivative of ln(3x+1) is 3/(3x+1)
What is the first derivative of ln(3x+1) ?
The first derivative of ln(3x+1) is 3/(3x+1)