What is the solution for (x^2+y+y^2)dx-xdy=0 ?

The solution for (x^2+y+y^2)dx-xdy=0 is y=tan(x+c_{1})x

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(x^2+y+y^2)dx-xdy=0

(x^{2} + y + y^{2}) d x - x d y = 0

y = tan (x + c_{1}) x

Solution steps

(x^{2} + y + y^{2}) d x - x d y = 0

Solve using substitution:

y = tan (x + c_{1}) x

y = tan (x + c_{1}) x

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What is the solution for (x^2+y+y^2)dx-xdy=0 ?
The solution for (x^2+y+y^2)dx-xdy=0 is y=tan(x+c_{1})x