What is area 3cos(8x),3-3cos(8x),[0, pi/8 ] ?

The answer to area 3cos(8x),3-3cos(8x),[0, pi/8 ] is (pi+6sqrt(3))/8

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area 3cos(8x),3-3cos(8x),[0, pi/8 ]

area

3 cos (8 x), 3 - 3 cos (8 x), [0, \frac{π}{8}]

\frac{π + 6 3}{8}

Decimal Notation

1.69173 \dots

Solution steps

Apply the area formula:

\int_{0}^{\frac{π}{8}} ∣ 3 cos (8 x) - (3 - 3 cos (8 x)) ∣ d x

Solve

\int_{0}^{\frac{π}{8}} ∣ 3 cos (8 x) - (3 - 3 cos (8 x)) ∣ d x : \frac{π + 6 3}{8}

The area is:

= \frac{π + 6 3}{8}

\frac{d}{d x} (\frac{4}{3} x^{3} - 4 x + 3)

f (x) = \frac{1}{x - 4}

\int_{0}^{\frac{π}{3}} sin (x) ln (cos (x)) d x

\int cos^{2} (ln (x)) d x

\frac{\partial}{\partial x} (y + (\frac{1}{\frac{1}{x} + \frac{1}{z}}))

What is area 3cos(8x),3-3cos(8x),[0, pi/8 ] ?
The answer to area 3cos(8x),3-3cos(8x),[0, pi/8 ] is (pi+6sqrt(3))/8