What is the derivative of x+sqrt(x)+8 ?

The derivative of x+sqrt(x)+8 is 1/(2sqrt(x))+1

What is the first derivative of x+sqrt(x)+8 ?

The first derivative of x+sqrt(x)+8 is 1/(2sqrt(x))+1

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\frac{d}{d x} (x + x + 8)

\frac{1}{2 x} + 1

Solution steps

\frac{d}{d x} (x + x + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (x) + \frac{d}{d x} (8)

\frac{d x}{d x} = 1

\frac{d}{d x} (x) = \frac{1}{2 x}

\frac{d}{d x} (8) = 0

= 1 + \frac{1}{2 x} + 0

Simplify

= \frac{1}{2 x} + 1

(5 x + y e^{\frac{y}{x}}) d x - x e^{\frac{y}{x}} d y = 0

y^{^{'}} = \frac{y}{x} + (\frac{2 x ^{3}}{y}) cos (x^{2})

x \to 0 lim ((2 x - 1)^{3})

x \to 9 - lim (\frac{- 3}{( x - 9 ) ^{2}})

\int_{- 1}^{1} 1 - y^{2} - (y^{2} - 1) d y

What is the derivative of x+sqrt(x)+8 ?
The derivative of x+sqrt(x)+8 is 1/(2sqrt(x))+1
What is the first derivative of x+sqrt(x)+8 ?
The first derivative of x+sqrt(x)+8 is 1/(2sqrt(x))+1