What is the derivative of f(x)=x^4-6x^2+9 ?

The derivative of f(x)=x^4-6x^2+9 is 4x^3-12x

What is the first derivative of f(x)=x^4-6x^2+9 ?

The first derivative of f(x)=x^4-6x^2+9 is 4x^3-12x

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derivative of

f (x) = x^{4} - 6 x^{2} + 9

4 x^{3} - 12 x

Solution steps

\frac{d}{d x} (x^{4} - 6 x^{2} + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (6 x^{2}) + \frac{d}{d x} (9)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d}{d x} (9) = 0

= 4 x^{3} - 12 x + 0

Simplify

= 4 x^{3} - 12 x

\frac{d}{d t} (in cos (t))

\int x^{4} 5^{x} d x

f (x) = (x^{2} - 48)^{4}, at x = 7

\frac{d}{d x} (\frac{x}{3 x + 4 ln ( x )})

\frac{d}{d x} (x + 11)

What is the derivative of f(x)=x^4-6x^2+9 ?
The derivative of f(x)=x^4-6x^2+9 is 4x^3-12x
What is the first derivative of f(x)=x^4-6x^2+9 ?
The first derivative of f(x)=x^4-6x^2+9 is 4x^3-12x