What is the integral of (xsqrt(x-1)) ?

The integral of (xsqrt(x-1)) is 2/5 (x-1)^{5/2}+2/3 (x-1)^{3/2}+C

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integral of (xsqrt(x-1))

\int (x x - 1) d x

\frac{2}{5} (x - 1)^{\frac{5}{2}} + \frac{2}{3} (x - 1)^{\frac{3}{2}} + C

Solution steps

\int x x - 1 d x

Apply u-substitution

: \int (u + 1) u d u

= \int (u + 1) u d u

Expand

(u + 1) u : u^{\frac{3}{2}} + u

= \int u^{\frac{3}{2}} + u d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int u^{\frac{3}{2}} d u + \int u d u

\int u^{\frac{3}{2}} d u = \frac{2}{5} u^{\frac{5}{2}}

\int u d u = \frac{2}{3} u^{\frac{3}{2}}

= \frac{2}{5} u^{\frac{5}{2}} + \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = x - 1

= \frac{2}{5} (x - 1)^{\frac{5}{2}} + \frac{2}{3} (x - 1)^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{5} (x - 1)^{\frac{5}{2}} + \frac{2}{3} (x - 1)^{\frac{3}{2}} + C

\frac{d}{d θ} (e^{θ})

f (x) = (e^{- x} - e^{3}) (e^{x} + e^{- 5})

\int (2 x - 3) (x^{2} - 3 x - 1)^{4} ln (x^{2} - 3 x - 1) d x

\int x e^{y^{2}} d x

\frac{d}{d x} ((x y)^{\frac{1}{2}})

What is the integral of (xsqrt(x-1)) ?
The integral of (xsqrt(x-1)) is 2/5 (x-1)^{5/2}+2/3 (x-1)^{3/2}+C