What is the derivative of (x-1^3) ?

The derivative of (x-1^3) is 3(x-1)^2

What is the first derivative of (x-1^3) ?

The first derivative of (x-1^3) is 3(x-1)^2

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\frac{d}{d x} ((x - 1)^{3})

3 (x - 1)^{2}

Solution steps

\frac{d}{d x} ((x - 1)^{3})

Apply the chain rule:

3 (x - 1)^{2} \frac{d}{d x} (x - 1)

= 3 (x - 1)^{2} \frac{d}{d x} (x - 1)

\frac{d}{d x} (x - 1) = 1

= 3 (x - 1)^{2} \cdot 1

Simplify

= 3 (x - 1)^{2}

\frac{d}{d x} (e^{(- 0.5 x)})

\int sin (2 x) sin (n x) d x

\frac{d y}{d t} + 0.7 t y = 9 t, y (0) = 5

\int \frac{1 + ( x + 1 ) ^{4}}{x + 1} d x

\frac{8 x}{9 - cot ( x )}

What is the derivative of (x-1^3) ?
The derivative of (x-1^3) is 3(x-1)^2
What is the first derivative of (x-1^3) ?
The first derivative of (x-1^3) is 3(x-1)^2