What is the derivative of-x+8/x+1 ?

The derivative of-x+8/x+1 is -8/(x^2)-1

What is the first derivative of-x+8/x+1 ?

The first derivative of-x+8/x+1 is -8/(x^2)-1

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\frac{d}{d x} (- x + \frac{8}{x} + 1)

- \frac{8}{x ^{2}} - 1

Solution steps

\frac{d}{d x} (- x + \frac{8}{x} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d x}{d x} + \frac{d}{d x} (\frac{8}{x}) + \frac{d}{d x} (1)

\frac{d x}{d x} = 1

\frac{d}{d x} (\frac{8}{x}) = - \frac{8}{x ^{2}}

\frac{d}{d x} (1) = 0

= - 1 - \frac{8}{x ^{2}} + 0

Simplify

= - \frac{8}{x ^{2}} - 1

y^{^{''}} + 10 y^{^{'}} + 24 y = 0

n = 1 \sum \infty 0.5

\int \frac{1}{25 e ^{- 3 x} + e ^{3 x}} d x

(- 3, 5), (2, - 4)

0.0225 t e^{- 0.0467 t}

What is the derivative of-x+8/x+1 ?
The derivative of-x+8/x+1 is -8/(x^2)-1
What is the first derivative of-x+8/x+1 ?
The first derivative of-x+8/x+1 is -8/(x^2)-1