What is the derivative of 1+2sin(x) ?

The derivative of 1+2sin(x) is 2cos(x)

What is the first derivative of 1+2sin(x) ?

The first derivative of 1+2sin(x) is 2cos(x)

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\frac{d}{d x} (1 + 2 sin (x))

2 cos (x)

Solution steps

\frac{d}{d x} (1 + 2 sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (2 sin (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (2 sin (x)) = 2 cos (x)

= 0 + 2 cos (x)

Simplify

= 2 cos (x)

\frac{d}{d x} (\frac{( x ^{3} )}{3} + \frac{1}{4 x})

\int \frac{1}{x ( x ^{999} + 1 ) ^{2}} d x

f (x) = 2 x^{3}, (1, 2)

\frac{d}{d y} (ln (\frac{( 2 y + 1 ) ^{4}}{y ^{2} + 1}))

\frac{2}{x - 5}

What is the derivative of 1+2sin(x) ?
The derivative of 1+2sin(x) is 2cos(x)
What is the first derivative of 1+2sin(x) ?
The first derivative of 1+2sin(x) is 2cos(x)