What is the derivative of x^3+x^2 ?

The derivative of x^3+x^2 is 3x^2+2x

What is the first derivative of x^3+x^2 ?

The first derivative of x^3+x^2 is 3x^2+2x

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derivative of

x^{3} + x^{2}

3 x^{2} + 2 x

Solution steps

\frac{d}{d x} (x^{3} + x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (x^{2})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (x^{2}) = 2 x

= 3 x^{2} + 2 x

x \to \infty lim (\frac{m}{n})

n = 0 \sum \infty 0.0 1^{n}

y + y^{^{'}} = sin (t), y (π) = 1

\int_{1}^{3 x} (t^{2} + t) d t

f (x) = 2 - 2 x^{2}, - 16, at x = 3

What is the derivative of x^3+x^2 ?
The derivative of x^3+x^2 is 3x^2+2x
What is the first derivative of x^3+x^2 ?
The first derivative of x^3+x^2 is 3x^2+2x