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Popular >

derivative of-2asin(2x+2bcos(2x))

Solution

\frac{d}{d x} (- 2 a sin (2 x) + 2 b cos (2 x))

Solution

- 4 a cos (2 x) - 4 b sin (2 x)

Solution steps

\frac{d}{d x} (- 2 a sin (2 x) + 2 b cos (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 a sin (2 x)) + \frac{d}{d x} (2 b cos (2 x))

\frac{d}{d x} (2 a sin (2 x)) = 4 a cos (2 x)

\frac{d}{d x} (2 b cos (2 x)) = - 4 b sin (2 x)

= - 4 a cos (2 x) - 4 b sin (2 x)

Popular Examples

derivative of y=sqrt(2+8e^{6x)}derivative of

y = 2 + 8 e^{6 x}

derivative of ((e^x-2)/((1-e^{-x))^2})

\frac{d}{d x} (\frac{( e ^{x} - 2 )}{( 1 - e ^{- x} ) ^{2}})

integral of 1/((x-1)^2)

\int \frac{1}{( x - 1 ) ^{2}} d x

(\partial)/(\partial x)(5xy)

\frac{\partial}{\partial x} (5 x y)

derivative of (e^{-x}-e^5(e^x+e^{-3}))

\frac{d}{d x} ((e^{- x} - e^{5}) (e^{x} + e^{- 3}))

Frequently Asked Questions (FAQ)

What is the derivative of-2asin(2x+2bcos(2x)) ?
The derivative of-2asin(2x+2bcos(2x)) is -4acos(2x)-4bsin(2x)
What is the first derivative of-2asin(2x+2bcos(2x)) ?
The first derivative of-2asin(2x+2bcos(2x)) is -4acos(2x)-4bsin(2x)