What is the tangent of y= 1/(x-2),\at x=4 ?

The tangent of y= 1/(x-2),\at x=4 is y=-1/4 x+3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y= 1/(x-2),\at x=4

tangent of

y = \frac{1}{x - 2}, at x = 4

y = - \frac{1}{4} x + \frac{3}{2}

Solution steps

Find the tangent point:

(4, \frac{1}{2})

Find the slope of

y = \frac{1}{x - 2} : \frac{d y}{d x} = - \frac{1}{( x - 2 ) ^{2}}

Compute the slope of

y = \frac{1}{x - 2}

x = 4 : m = - \frac{1}{4}

Find the line with slope m=

- \frac{1}{4}

and passing through

(4, \frac{1}{2}) : y = - \frac{1}{4} x + \frac{3}{2}

y = - \frac{1}{4} x + \frac{3}{2}

y = 5 - 3 x^{2}

y^{^{''}} + 2 y^{^{'}} + 2 y = sin (k x)

\int sec (2 x) tan (2 x) - \frac{4}{x ^{2}} d x

\int (cos (y)) d y

(- 3, 5), (7, - 9)

What is the tangent of y= 1/(x-2),\at x=4 ?
The tangent of y= 1/(x-2),\at x=4 is y=-1/4 x+3/2