What is the derivative of (x^2/(x-1)) ?

The derivative of (x^2/(x-1)) is (x^2-2x)/((x-1)^2)

What is the first derivative of (x^2/(x-1)) ?

The first derivative of (x^2/(x-1)) is (x^2-2x)/((x-1)^2)

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\frac{d}{d x} (\frac{x ^{2}}{x - 1})

\frac{x ^{2} - 2 x}{( x - 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{x - 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} ) ( x - 1 ) - \frac{d}{d x} ( x - 1 ) x ^{2}}{( x - 1 ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x - 1) = 1

= \frac{2 x ( x - 1 ) - 1 \cdot x ^{2}}{( x - 1 ) ^{2}}

Simplify

\frac{2 x ( x - 1 ) - 1 \cdot x ^{2}}{( x - 1 ) ^{2}} : \frac{x ^{2} - 2 x}{( x - 1 ) ^{2}}

= \frac{x ^{2} - 2 x}{( x - 1 ) ^{2}}

\int cos (c x) d x

\frac{d}{d x} (sin (\frac{π}{3}))

\int \frac{x ^{2} - 324}{x} d x

\frac{d}{d x} (3 cos (x) + 4 x^{2})

x^{4} + 5 y^{4} x^{5} + 4 y^{^{'}} = 0, y (0) = 1

What is the derivative of (x^2/(x-1)) ?
The derivative of (x^2/(x-1)) is (x^2-2x)/((x-1)^2)
What is the first derivative of (x^2/(x-1)) ?
The first derivative of (x^2/(x-1)) is (x^2-2x)/((x-1)^2)