What is (\partial)/(\partial x)(xy+x^2) ?

The answer to (\partial)/(\partial x)(xy+x^2) is y+2x

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(\partial)/(\partial x)(xy+x^2)

\frac{\partial}{\partial x} (x y + x^{2})

y + 2 x

Solution steps

\frac{\partial}{\partial x} (x y + x^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x y) + \frac{\partial}{\partial x} (x^{2})

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (x^{2}) = 2 x

= y + 2 x

9 (x^{2} + y^{2}) d x + 7 x y d y = 0

n = 1 \sum \infty \frac{64}{n ^{3}}

\int \frac{6 x ^{2} - 3 x + 1}{( 4 x + 1 ) ( x ^{2} + 1 )} d x

y = 2^{3 x^{2}}

\int \frac{( cos ^{5} ( t ) )}{sin ( t )} d t

What is (\partial)/(\partial x)(xy+x^2) ?
The answer to (\partial)/(\partial x)(xy+x^2) is y+2x