What is the derivative of 2cos(x/2+pi) ?

The derivative of 2cos(x/2+pi) is -sin(x/2)

What is the first derivative of 2cos(x/2+pi) ?

The first derivative of 2cos(x/2+pi) is -sin(x/2)

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\frac{d}{d x} (2 cos (\frac{x}{2}) + π)

- sin (\frac{x}{2})

Solution steps

\frac{d}{d x} (2 cos (\frac{x}{2}) + π)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 cos (\frac{x}{2})) + \frac{d}{d x} (π)

\frac{d}{d x} (2 cos (\frac{x}{2})) = - sin (\frac{x}{2})

\frac{d}{d x} (π) = 0

= - sin (\frac{x}{2}) + 0

Simplify

= - sin (\frac{x}{2})

n = 0 \sum \infty (- \frac{5}{9})^{n}

\int_{2}^{7} x^{2} d x

y = x e^{x} - e^{x}

\int x^{7} x^{4} + 5 d x

\int_{l n (2)}^{3} 5 e^{x} d x

What is the derivative of 2cos(x/2+pi) ?
The derivative of 2cos(x/2+pi) is -sin(x/2)
What is the first derivative of 2cos(x/2+pi) ?
The first derivative of 2cos(x/2+pi) is -sin(x/2)