What is the derivative of (x^2+2^2) ?

The derivative of (x^2+2^2) is 4x(x^2+2)

What is the first derivative of (x^2+2^2) ?

The first derivative of (x^2+2^2) is 4x(x^2+2)

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\frac{d}{d x} ((x^{2} + 2)^{2})

4 x (x^{2} + 2)

Solution steps

\frac{d}{d x} ((x^{2} + 2)^{2})

Apply the chain rule:

2 (x^{2} + 2) \frac{d}{d x} (x^{2} + 2)

= 2 (x^{2} + 2) \frac{d}{d x} (x^{2} + 2)

\frac{d}{d x} (x^{2} + 2) = 2 x

= 2 (x^{2} + 2) \cdot 2 x

Simplify

= 4 x (x^{2} + 2)

\frac{\partial}{\partial y} (2 x y ln (y))

\frac{5}{12} (3 + 5) x^{3}

\frac{\partial}{\partial v} (3 v cos (u))

\frac{( 1 + x )}{x}

\int \frac{y + 3}{( 3 - y ) ^{\frac{2}{3}}} d y

What is the derivative of (x^2+2^2) ?
The derivative of (x^2+2^2) is 4x(x^2+2)
What is the first derivative of (x^2+2^2) ?
The first derivative of (x^2+2^2) is 4x(x^2+2)