What is the integral of (e^{-4x})/(x^2) ?

The integral of (e^{-4x})/(x^2) is -(e^{-4x})/x-4\Ei(-4x)+C

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integral of (e^{-4x})/(x^2)

\int \frac{e ^{- 4 x}}{x ^{2}} d x

- \frac{e ^{- 4 x}}{x} - 4 Ei (- 4 x) + C

Solution steps

\int \frac{e ^{- 4 x}}{x ^{2}} d x

Apply Integration By Parts

: - \frac{e ^{- 4 x}}{x} - \int \frac{4 e ^{- 4 x}}{x} d x

= - \frac{e ^{- 4 x}}{x} - \int \frac{4 e ^{- 4 x}}{x} d x

\int \frac{4 e ^{- 4 x}}{x} d x = 4 Ei (- 4 x)

= - \frac{e ^{- 4 x}}{x} - 4 Ei (- 4 x)

Add a constant to the solution

= - \frac{e ^{- 4 x}}{x} - 4 Ei (- 4 x) + C

y = - x^{3} + 3, y = x, x = - 1, x = 1

y^{4} - 4 y^{2} = x^{4} - 9 x^{2}, (- 3, - 2)

\int \frac{- sin ^{2} ( x )}{cos ( x )} d x

y = sin (sin (x))

\frac{\partial}{\partial x} (ln (8 x^{2} + 7 y^{2} + 9))

What is the integral of (e^{-4x})/(x^2) ?
The integral of (e^{-4x})/(x^2) is -(e^{-4x})/x-4\Ei(-4x)+C