What is (\partial)/(\partial y)(3xcos(y)) ?

The answer to (\partial)/(\partial y)(3xcos(y)) is -3xsin(y)

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(\partial)/(\partial y)(3xcos(y))

\frac{\partial}{\partial y} (3 x cos (y))

- 3 x sin (y)

Solution steps

\frac{\partial}{\partial y} (3 x cos (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 x \frac{\partial}{\partial y} (cos (y))

Apply the common derivative:

\frac{\partial}{\partial y} (cos (y)) = - sin (y)

= 3 x (- sin (y))

Simplify

= - 3 x sin (y)

\int \frac{21}{x ( x ^{2} + 4 ) ^{2}} d x

\frac{d}{d x} (ln (\frac{( x + 2 )}{x ^{2}}))

y^{^{'}} - y = 9 t e^{2 t}

x \to 1 + lim (\frac{1}{1 - x ^{2}})

f (x) = x e^{x^{2}}

What is (\partial)/(\partial y)(3xcos(y)) ?
The answer to (\partial)/(\partial y)(3xcos(y)) is -3xsin(y)