What is the f(x)=((5x^2+6x+1)/(3x-5))^{3/2} ?

The f(x)=((5x^2+6x+1)/(3x-5))^{3/2} is

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f(x)=((5x^2+6x+1)/(3x-5))^{3/2}

f (x) = (\frac{5 x ^{2} + 6 x + 1}{3 x - 5})^{\frac{3}{2}}

Domain : - 1 \leq x \leq - \frac{1}{5} or x > \frac{5}{3}

X Intercepts : (- \frac{1}{5}, 0), (- 1, 0)

Asymptotes : None

Extreme Points : Minimum \frac{25 + 4 \cdot 7 0 ^{\frac{1}{2}}}{15}, \frac{8 ( 70 \cdot 2 ^{\frac{1}{2}} + 17 \cdot 3 5 ^{\frac{1}{2}} ) ^{\frac{3}{2}}}{27 \cdot 3 5 ^{\frac{3}{4}}}

Interval Notation

Domain : [- 1, - \frac{1}{5}] \cup (\frac{5}{3}, \infty)

Solution steps

Domain of

(\frac{5 x ^{2} + 6 x + 1}{3 x - 5})^{\frac{3}{2}} : - 1 \leq x \leq - \frac{1}{5} or x > \frac{5}{3}

Axis interception points of

(\frac{5 x ^{2} + 6 x + 1}{3 x - 5})^{\frac{3}{2}} :

X Intercepts

: (- \frac{1}{5}, 0), (- 1, 0)

Asymptotes of

(\frac{5 x ^{2} + 6 x + 1}{3 x - 5})^{\frac{3}{2}} :

None

Extreme Points of

(\frac{5 x ^{2} + 6 x + 1}{3 x - 5})^{\frac{3}{2}} :

Minimum

\frac{25 + 4 \cdot 7 0 ^{\frac{1}{2}}}{15}, \frac{8 ( 70 \cdot 2 ^{\frac{1}{2}} + 17 \cdot 3 5 ^{\frac{1}{2}} ) ^{\frac{3}{2}}}{27 \cdot 3 5 ^{\frac{3}{4}}}

\int - \frac{1}{2} x^{2} d x

\int \frac{6 x + 4}{3 x ^{2} + 4 x + 2} d x

\frac{\partial}{\partial x} (x \cdot ln (x + 2 y))

y^{^{'}} = \frac{4 t + y}{4 y - t}

\frac{\partial}{\partial y} (sin (x^{2} + y^{2}))

What is the f(x)=((5x^2+6x+1)/(3x-5))^{3/2} ?
The f(x)=((5x^2+6x+1)/(3x-5))^{3/2} is