What is the solution for (dy)/(dt)+3y=5,y(0)=1 ?

The solution for (dy)/(dt)+3y=5,y(0)=1 is y=-(2e^{-3t})/3+5/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dt)+3y=5,y(0)=1

\frac{d y}{d t} + 3 y = 5, y (0) = 1

y = - \frac{2 e ^{- 3 t}}{3} + \frac{5}{3}

Solution steps

\frac{d y}{d t} + 3 y = 5

Solve separable ODE:

y = - \frac{2 e ^{- 3 t}}{3} + \frac{5}{3}

y = - \frac{2 e ^{- 3 t}}{3} + \frac{5}{3}

y^{^{''}} + 16 y = - 24 sin (4 t)

\int x^{2} x^{3} + 2 d x

n = 0 \sum \infty \frac{1}{4 ^{n + 1}}

\frac{d}{d x} (e^{x^{2} - 2 x + 1})

\frac{\partial}{\partial x} (x^{3} y^{2} e^{x z})

What is the solution for (dy)/(dt)+3y=5,y(0)=1 ?
The solution for (dy)/(dt)+3y=5,y(0)=1 is y=-(2e^{-3t})/3+5/3