What is the tangent of f(x)=2x^2+x-1,\at x=1 ?

The tangent of f(x)=2x^2+x-1,\at x=1 is y=5x-3

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tangent of f(x)=2x^2+x-1,\at x=1

tangent of

f (x) = 2 x^{2} + x - 1, at x = 1

y = 5 x - 3

Solution steps

Find the tangent point:

(1, 2)

Find the slope of

f (x) = 2 x^{2} + x - 1 : \frac{df ( x )}{d x} = 4 x + 1

Compute the slope of

f (x) = 2 x^{2} + x - 1

x = 1 : m = 5

Find the line with slope m=

5

and passing through

(1, 2) : y = 5 x - 3

y = 5 x - 3

(5.6) (6.9)

\int 2 r d r

7 ln (x)

y^{^{''}} + 3 y^{^{'}} + 4 y = 0

\int sin (x) cos (x) d x

What is the tangent of f(x)=2x^2+x-1,\at x=1 ?
The tangent of f(x)=2x^2+x-1,\at x=1 is y=5x-3