What is the (sin(x)+cos(x))^' ?

The (sin(x)+cos(x))^' is cos(x)-sin(x)

What is the first (sin(x)+cos(x))^' ?

The first (sin(x)+cos(x))^' is cos(x)-sin(x)

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(sin (x) + cos (x))^{^{'}}

cos (x) - sin (x)

Solution steps

(sin (x) + cos (x))^{'}

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= (sin (x))^{^{'}} + (cos (x))^{^{'}}

(sin (x))^{'} = cos (x)

(cos (x))^{'} = - sin (x)

= cos (x) - sin (x)

\int \frac{( x + sin ( x ) )}{( 1 + cos ( x ) )} d x

\int \frac{x + 3}{x ^{2} ( x + 1 ) ^{2}} d x

\frac{\partial}{\partial x} (- \frac{a}{x})

y = x^{2} - 8 x, (3, - 15)

\int \frac{1}{x ^{3} + 8 x} d x

What is the (sin(x)+cos(x))^' ?
The (sin(x)+cos(x))^' is cos(x)-sin(x)
What is the first (sin(x)+cos(x))^' ?
The first (sin(x)+cos(x))^' is cos(x)-sin(x)