What is the integral from 1 to 3 of 2x^2-2x+3 ?

The integral from 1 to 3 of 2x^2-2x+3 is 46/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 3 of 2x^2-2x+3

\int_{1}^{3} 2 x^{2} - 2 x + 3 d x

\frac{46}{3}

Decimal Notation

15.33333 \dots

Solution steps

\int_{1}^{3} 2 x^{2} - 2 x + 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} 2 x^{2} d x - \int_{1}^{3} 2 x d x + \int_{1}^{3} 3 d x

\int_{1}^{3} 2 x^{2} d x = \frac{52}{3}

\int_{1}^{3} 2 x d x = 8

\int_{1}^{3} 3 d x = 6

= \frac{52}{3} - 8 + 6

Simplify

\frac{52}{3} - 8 + 6 : \frac{46}{3}

= \frac{46}{3}

\int_{0}^{1} (sin (2 π t))^{2} d t

\frac{460 t}{( t ^{2} + 5 ) ^{3}}

\int 3 x + 9 d x

\frac{d}{d x} (ln (sin (x) + cos (x)))

\int - x^{2} + 6 x d x

What is the integral from 1 to 3 of 2x^2-2x+3 ?
The integral from 1 to 3 of 2x^2-2x+3 is 46/3