What is the derivative of-4/((4x-3)^{3/2)} ?

The derivative of-4/((4x-3)^{3/2)} is (24)/((4x-3)^{5/2)}

What is the first derivative of-4/((4x-3)^{3/2)} ?

The first derivative of-4/((4x-3)^{3/2)} is (24)/((4x-3)^{5/2)}

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derivative of

- \frac{4}{( 4 x - 3 ) ^{\frac{3}{2}}}

\frac{24}{( 4 x - 3 ) ^{\frac{5}{2}}}

Solution steps

\frac{d}{d x} (- \frac{4}{( 4 x - 3 ) ^{\frac{3}{2}}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 \frac{d}{d x} (\frac{1}{( 4 x - 3 ) ^{\frac{3}{2}}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 4 \frac{d}{d x} ((4 x - 3)^{- \frac{3}{2}})

Apply the chain rule:

- \frac{3}{2 ( 4 x - 3 ) ^{\frac{5}{2}}} \frac{d}{d x} (4 x - 3)

= - \frac{3}{2 ( 4 x - 3 ) ^{\frac{5}{2}}} \frac{d}{d x} (4 x - 3)

\frac{d}{d x} (4 x - 3) = 4

= - 4 (- \frac{3}{2 ( 4 x - 3 ) ^{\frac{5}{2}}} \cdot 4)

Simplify

- 4 (- \frac{3}{2 ( 4 x - 3 ) ^{\frac{5}{2}}} \cdot 4) : \frac{24}{( 4 x - 3 ) ^{\frac{5}{2}}}

= \frac{24}{( 4 x - 3 ) ^{\frac{5}{2}}}

\frac{ln ( 4 x )}{x}

\frac{\partial}{\partial t} (\frac{( 2 r + s )}{t})

x \to 0 lim (2 (tan (x))^{x})

\int x^{2} e^{22 x} d x

y = \frac{x ^{3} + 1}{x ^{2} - 1}

What is the derivative of-4/((4x-3)^{3/2)} ?
The derivative of-4/((4x-3)^{3/2)} is (24)/((4x-3)^{5/2)}
What is the first derivative of-4/((4x-3)^{3/2)} ?
The first derivative of-4/((4x-3)^{3/2)} is (24)/((4x-3)^{5/2)}