What is the solution for ((x^2+1)dy)/(dx)+3x(y-1)=0 ?

The solution for ((x^2+1)dy)/(dx)+3x(y-1)=0 is y=(c_{1})/((x^2+1)^{3/2)}+1

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((x^2+1)dy)/(dx)+3x(y-1)=0

\frac{( x ^{2} + 1 ) d y}{d x} + 3 x (y - 1) = 0

y = \frac{c _{1}}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 1

Solution steps

\frac{( x ^{2} + 1 ) d y}{d x} + 3 x (y - 1) = 0

Solve separable ODE:

y = \frac{c _{1}}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 1

y = \frac{c _{1}}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 1

\frac{d}{d x} (arcsin (\frac{x ^{2} + y ^{2}}{2}))

y = \frac{6 x}{x ^{2} + 1}, (1, 3)

\int \frac{1}{2 \cdot x} d x

\frac{1}{x + 3}

e^{- 3 t} cos (2 t)

What is the solution for ((x^2+1)dy)/(dx)+3x(y-1)=0 ?
The solution for ((x^2+1)dy)/(dx)+3x(y-1)=0 is y=(c_{1})/((x^2+1)^{3/2)}+1