What is the derivative of 6cos(3x) ?

The derivative of 6cos(3x) is -18sin(3x)

What is the first derivative of 6cos(3x) ?

The first derivative of 6cos(3x) is -18sin(3x)

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derivative of

6 cos (3 x)

- 18 sin (3 x)

Solution steps

\frac{d}{d x} (6 cos (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (cos (3 x))

Apply the chain rule:

- sin (3 x) \frac{d}{d x} (3 x)

= - sin (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= 6 (- sin (3 x) \cdot 3)

Simplify

= - 18 sin (3 x)

\frac{d y}{d x} = x y^{2}

\int \frac{( x ^{2} - 16 )}{x ^{3}} d x

y^{^{'}} = 6 y + 2 t - 4, y (0) = 3

\int_{0}^{1} 1 - x d x

\frac{d}{d x} ((2 - x)^{\frac{3}{2}})

What is the derivative of 6cos(3x) ?
The derivative of 6cos(3x) is -18sin(3x)
What is the first derivative of 6cos(3x) ?
The first derivative of 6cos(3x) is -18sin(3x)