What is (\partial)/(\partial x)(4x-8y^3) ?

The answer to (\partial)/(\partial x)(4x-8y^3) is 4

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(\partial)/(\partial x)(4x-8y^3)

\frac{\partial}{\partial x} (4 x - 8 y^{3})

4

Solution steps

\frac{\partial}{\partial x} (4 x - 8 y^{3})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4 x) - \frac{\partial}{\partial x} (8 y^{3})

\frac{\partial}{\partial x} (4 x) = 4

\frac{\partial}{\partial x} (8 y^{3}) = 0

= 4 - 0

Simplify

= 4

y^{^{''}} - 6 y = 0

\frac{x ^{2}}{x - 4}

\frac{d}{d x} (2 sin (x) + 2 sin (x) cos (x))

3^{x}

\int \frac{x ^{2} + 2}{x ^{2} + 1} d x

What is (\partial)/(\partial x)(4x-8y^3) ?
The answer to (\partial)/(\partial x)(4x-8y^3) is 4