What is the first derivative of x^2+c ?

The first derivative of x^2+c is 2x

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derivative of x^2+c

\frac{d}{d x} (x^{2} + c)

2 x

Solution steps

\frac{d}{d x} (x^{2} + c)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d c}{d x}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d c}{d x} = 0

= 2 x + 0

Simplify

= 2 x

x \to 2 lim (\frac{2 + x}{2 - 4})

n = 0 \sum \infty 2 (\frac{1}{3 ^{n}})

\frac{d}{d z} (e^{z})

sin (2 x - 1)

f (x) = arccot (x)