What is the solution for (dy)/(dx)=((x+xy))/((y+xy)) ?

The solution for (dy)/(dx)=((x+xy))/((y+xy)) is y=-\W(-(x+1)/(e^{-c_{1)+x+1}})-1

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(dy)/(dx)=((x+xy))/((y+xy))

\frac{d y}{d x} = \frac{( x + x y )}{( y + x y )}

y = - W (- \frac{x + 1}{e ^{- c_{1} + x + 1}}) - 1

Solution steps

\frac{d y}{d x} = \frac{( x + x y )}{( y + x y )}

Solve separable ODE:

y = - W (- \frac{x + 1}{e ^{- c_{1} + x + 1}}) - 1

y = - W (- \frac{x + 1}{e ^{- c_{1} + x + 1}}) - 1

\int 5 cos (x) d x

x^{2} + 2 y^{2} = x y y^{^{'}}

\frac{d}{d x} ((x - 2)^{\frac{2}{3}})

y = e^{7 x} + 7 x e^{7 x}

f (x) = 6 e^{- 0.6 x}, at x = 4

What is the solution for (dy)/(dx)=((x+xy))/((y+xy)) ?
The solution for (dy)/(dx)=((x+xy))/((y+xy)) is y=-\W(-(x+1)/(e^{-c_{1)+x+1}})-1