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Popular >

integral of (y-1)

Solution

\int (y - 1) d y

Solution

\frac{y ^{2}}{2} - y + C

Solution steps

\int y - 1 d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int y d y - \int 1 d y

\int y d y = \frac{y ^{2}}{2}

\int 1 d y = y

= \frac{y ^{2}}{2} - y

Add a constant to the solution

= \frac{y ^{2}}{2} - y + C

Popular Examples

integral of-0.5y

\int - 0.5 y d y

integral of (10\sqrt[3]{x^2})

(\partial)/(\partial x)(xe^{4x})

\frac{\partial}{\partial x} (x e^{4 x})

area 2x=y,x+y=4,x+y=12 area

2 x = y, x + y = 4, x + y = 12

integral of ((3x^2+2x-3))/(x^3-x)

\int \frac{( 3 x ^{2} + 2 x - 3 )}{x ^{3} - x} d x

Frequently Asked Questions (FAQ)

What is the integral of (y-1) ?
The integral of (y-1) is (y^2)/2-y+C