What is the derivative of 2x-4sin(x) ?

The derivative of 2x-4sin(x) is 2-4cos(x)

What is the first derivative of 2x-4sin(x) ?

The first derivative of 2x-4sin(x) is 2-4cos(x)

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\frac{d}{d x} (2 x - 4 sin (x))

2 - 4 cos (x)

Solution steps

\frac{d}{d x} (2 x - 4 sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) - \frac{d}{d x} (4 sin (x))

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (4 sin (x)) = 4 cos (x)

= 2 - 4 cos (x)

A x^{n} + B e^{x}

\frac{d}{d x} (\frac{x ^{2}}{x - 3})

(6 x + 5) (x^{2} - 3 x)

\int 9 x^{5} d x

\int sin (r^{2}) d r

What is the derivative of 2x-4sin(x) ?
The derivative of 2x-4sin(x) is 2-4cos(x)
What is the first derivative of 2x-4sin(x) ?
The first derivative of 2x-4sin(x) is 2-4cos(x)