What is (\partial)/(\partial y)(yze^{xz}) ?

The answer to (\partial)/(\partial y)(yze^{xz}) is e^{zx}z

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(\partial)/(\partial y)(yze^{xz})

\frac{\partial}{\partial y} (yz e^{x z})

e^{z x} z

Solution steps

\frac{\partial}{\partial y} (yz e^{x z})

Treat

z, x

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= z e^{x z} \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= z e^{x z} \cdot 1

Simplify

= e^{z x} z

\int sin (\frac{π t}{2}) d t

y^{^{''}} - \frac{2}{t ^{2}} y = 0, y (- 1) = - 1, y^{^{'}} (- 1) = - 4

\int \frac{2 x ^{2} + x + 1}{( x + 3 ) ( x - 1 ) ^{2}} d x

n = 1 \sum \infty 1 6^{n} x^{n} n!

\frac{d y}{d x} = 6 x - 30

What is (\partial)/(\partial y)(yze^{xz}) ?
The answer to (\partial)/(\partial y)(yze^{xz}) is e^{zx}z