What is the integral from-infinity to 0 of x/(1+x^2) ?

The integral from-infinity to 0 of x/(1+x^2) is diverges

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integral from-infinity to 0 of x/(1+x^2)

\int_{- \infty}^{0} \frac{x}{1 + x ^{2}} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{x}{1 + x ^{2}} d x

Compute the indefinite integral:

\int \frac{x}{1 + x ^{2}} d x = \frac{1}{2} ln 1 + x^{2} + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{x}{1 + x ^{2}} d x =

diverges

= diverges

\frac{d}{d x} (\frac{x ^{2}}{x ^{2}})

- \frac{3}{x}

\int \frac{x + 4}{( x ^{2} + 8 x - 7 ) ^{2}} d x

\frac{d}{d t} (t + 2)

What is the integral from-infinity to 0 of x/(1+x^2) ?
The integral from-infinity to 0 of x/(1+x^2) is diverges