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Popular >

y^'=e^{-2x}

Solution

y^{^{'}} = e^{- 2 x}

Solution

y = - \frac{1}{2} e^{- 2 x} + c_{1}

Solution steps

y^{'} (x) = e^{- 2 x}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int e^{- 2 x} d x

\int e^{- 2 x} d x = - \frac{1}{2} e^{- 2 x} + c_{1}

y = - \frac{1}{2} e^{- 2 x} + c_{1}

Popular Examples

derivative of 26e^{x^2}x derivative of

26 e^{x^{2}} x

tangent of f(x)=x^2+1 tangent of

f (x) = x^{2} + 1

7y^{''}+5y^'+7y=0

7 y^{^{''}} + 5 y^{^{'}} + 7 y = 0

limit as h approaches 0 of (4/(2+h)-2)/h

h \to 0 lim (\frac{\frac{4}{2 + h} - 2}{h})

area x=1-y^2,-x-1 area

x = 1 - y^{2}, - x - 1

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{-2x} ?
The solution for y^'=e^{-2x} is y=-1/2 e^{-2x}+c_{1}