What is (\partial)/(\partial z)(xycos(z)) ?

The answer to (\partial)/(\partial z)(xycos(z)) is -xysin(z)

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(\partial)/(\partial z)(xycos(z))

\frac{\partial}{\partial z} (x y cos (z))

- x y sin (z)

Solution steps

\frac{\partial}{\partial z} (x y cos (z))

Treat

x, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x y \frac{\partial}{\partial z} (cos (z))

Apply the common derivative:

\frac{\partial}{\partial z} (cos (z)) = - sin (z)

= x y (- sin (z))

Simplify

= - x y sin (z)

\int x^{6} - 4 x^{4} + x + 1 d x

\int \frac{t ^{5}}{t ^{2} + 10} d t

\frac{d y}{d x} = 0.5 (100 - y)

\int_{1}^{5} x ln (x) d x

f (x) = x (x + 3)^{2}

What is (\partial)/(\partial z)(xycos(z)) ?
The answer to (\partial)/(\partial z)(xycos(z)) is -xysin(z)