What is the derivative of y=sqrt(ln(7x)) ?

The derivative of y=sqrt(ln(7x)) is 1/(2xsqrt(ln(7x)))

What is the first derivative of y=sqrt(ln(7x)) ?

The first derivative of y=sqrt(ln(7x)) is 1/(2xsqrt(ln(7x)))

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derivative of

y = ln (7 x)

\frac{1}{2 x ln ( 7 x )}

Solution steps

\frac{d}{d x} (ln (7 x))

Apply the chain rule:

\frac{1}{2 ln ( 7 x )} \frac{d}{d x} (ln (7 x))

= \frac{1}{2 ln ( 7 x )} \frac{d}{d x} (ln (7 x))

\frac{d}{d x} (ln (7 x)) = \frac{1}{x}

= \frac{1}{2 ln ( 7 x )} \cdot \frac{1}{x}

Simplify

\frac{1}{2 ln ( 7 x )} \cdot \frac{1}{x} : \frac{1}{2 x ln ( 7 x )}

= \frac{1}{2 x ln ( 7 x )}

\frac{d}{d x} (e^{x^{3} + 3 x})

x \to 2 lim (\frac{∣ x - 2 ∣}{2})

10 (1.05)^{x}

\int_{0}^{π} cos (t) sin (t) d t

n = 0 \sum \infty \frac{x ^{n}}{n}

What is the derivative of y=sqrt(ln(7x)) ?
The derivative of y=sqrt(ln(7x)) is 1/(2xsqrt(ln(7x)))
What is the first derivative of y=sqrt(ln(7x)) ?
The first derivative of y=sqrt(ln(7x)) is 1/(2xsqrt(ln(7x)))