What is the solution for 2y^{''}+17y^'-9y=0 ?

The solution for 2y^{''}+17y^'-9y=0 is y=c_{1}e^{t/2}+c_{2}e^{-9t}

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2y^{''}+17y^'-9y=0

2 y^{^{''}} + 17 y^{^{'}} - 9 y = 0

y = c_{1} e^{\frac{t}{2}} + c_{2} e^{- 9 t}

Solution steps

2 y^{''} (t) + 17 y^{'} (t) - 9 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{t}{2}} + c_{2} e^{- 9 t}

y = c_{1} e^{\frac{t}{2}} + c_{2} e^{- 9 t}

\frac{d}{d y} (x y + y z + x z)

y^{^{'}} = 3 e^{x - y}

f (x) = tan (4 x)

\frac{d y}{d t} = 3 + 5 y

8^{2 s - 1}

What is the solution for 2y^{''}+17y^'-9y=0 ?
The solution for 2y^{''}+17y^'-9y=0 is y=c_{1}e^{t/2}+c_{2}e^{-9t}